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Saturated steam pipe flow and velocity of the fast reduction algorithm


Base flow: G100 == O. 5pt / by the = 14X0.5 = 7t / h from (4) two channels of the projections can be obtained flow: = G100 × (oh/lO0) 6 × (125/100) 2 a l0.93t/h50 = 6 ... WXG/12535 × 10/10.9332m/s150 = 35 × t0/15.75 = 22m/s3 choice of steam flow rate of steam flow rate directly affects the size of the steam pressure drop and diameter, so consider carefully when selecting their Select the following principles: (1) small diameter, flow rate should be low, large diameter, flow rate should be high. (2) powered by the steam pipe, the pressure drop constraints, the flow rate should be slightly lower. (3) used for heating steam pipe, due to strict requirements of the user pressure, flow rate may be higher. (4), and diffuse the exhaust pipe flow is generally higher. According to the usual experience, the flow rate of saturated steam to make the following recommendations: 4 saturated steam pipe simple steps quick calculation diameter of known pressure and flow requirements: first step: Find the basic flow, namely G100 = 0.5P; the second step: find the projected traffic, that is, = G100 × (da/100); the third step: calculate the actual flow rate, that is, = w × / G. Example four: a unit to use the table of saturated steam pressure 9ata 4t,[link widoczny dla zalogowanych], please roughing diameter. Solution: Note title in the said pressure gauge pressure,[link widoczny dla zalogowanych], absolute pressure can be approximately replaced with lata atmospheric pressure, absolute pressure was lOata. The first step, find the base flow, which Gl00 = 0.5P = 0.5X10 = 5t / h, the demand is greater than the actual values, indicating that available than DNl004, the tube,[link widoczny dla zalogowanych], take DN80; the second step, find the projected traffic , ie = G100 × (da/1O0) 2 = 5 × 0.82 = 3.2t / h, smaller than the actual value, or select 【l) (】, but the basis of the actual flow velocity than 35m / s small; s three steps, find the actual flow rate: W100 = wG / a 35X4/G100-35 × 4 / 5 = 28m / s. Example five: a unit to use the table of saturated steam pressure 8ata 5t, please roughing diameter '. Step One: Find the basic flow, that is, G100 = 0.5P = 0.5X (8 +1) for a 4.5t / h, the smaller value than the actual value of demand, indicating that the actual use of large diameter than the DNl00, test selection DNl25 and DN150} Step Two: Find the projected traffic that Ga = 6100X (da/lO0), G125 = G100X (da/100) 2 = 4.5X (125/100): 5.6t/h.G150 = G100X (da/100) = 4.5X (150/100)-6.7t / h, from the quantity can meet the requirements; the third step: calculate the actual flow rate, which XGb / G., W125wXGb / = 31m / s , W150 = w × / G. = 26m / s, can be seen both are in the recommended flow velocity, if the distance was longer, on the pressure for high user options DNl5O,[link widoczny dla zalogowanych], the average user can choose DNl25. known diameter actual flow demand, then there is a paper mill saturated steam DN80, pressure gauge shows a reading of 8ata, Find the steam flow. The first step: Find the base flow,[link widoczny dla zalogowanych], ie G100 = 0.5JD a 4.5t / h; second Step three: Find the projected traffic, that is, = G100 × (da/100) 24.5 × (80/100) 1 = 2.88t / h; the third step: calculate the actual flow, that is, = × /, under the saturated steam Recommended flow rate table, DN80 pipe recommended flow 2O ~ 30, values ​​25, = Xa / w = 2.1t / h. above reduction algorithm in real life, helpful, convenient, of course, only as a closer estimates, in the case of high demand but also the length of the pipe and fittings to find the resistance loss of a more comprehensive description of the problem.
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