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Graded PS- Ring


A muscle of a L-R () 10 can be split , so L is a graded direct summand . According to Lemma 2, there is , =, ∈ see so L = · (3) (4) This is due to non-trivial sub- sub- sub- straight and entry is not the essence of Rotary . (4 ) (5 ) This is because the sub- sub- sub- maximal left ideal either for nature or for the sub- sub- sub- direct summand . (5 ) Sim (6 ) If '∈ r (L) n (), because r (L) = J Xiao . , L a , ∈ see ,[link widoczny dla zalogowanych], so l cents , · r. =. , L · r a , · tl II r (L) · b) (3) if (L) ≠ 0, so that 0 ≠ mouth ∈ r (L) recorded 8 = + + ... +. , ∈. , L; 1,2 '. . * , 4, then 0 ≠ ∈ r (L) ( because L is a sub- maximal left ideal 『 reward ) . Questions set by the ∈ r (L), that is . A ,), l ∈ L, to = + r ( as ) 10 , contradiction. Therefore, ( 1 a ,) L, so (1 a ,), ∈ L ·, = {0}, that is , = . Also known by the = 0 L-L (1 a ,) £ (1 a ,). and thus L = (1 a ,) , ie r (L) =, R , and , =, ∈ , see . (3 ) Sim (7 ) Let = Ferret I, m ∈ to the list -mode and L = f (m), define ,: R a threat , rf-r''m ' is ∈ Hom (R, threat ) , that is, ∈ Horn-, (, Rm (o Then add a 1) lan (1 a , ) is a graded project , that sampan = is a graded projective , if r (L) = 0. Order ∈. If ( figurines ) on a ∈ Island, then = L ( ( timid ))=(£) a (0 ) = 0 , so the port = 0. This means that = 0 , so = 0. (7 ) (8 ) This is apparently because the Hoh (. R) ≠ 0对All were graded left ideal of a single set up. (8 ) (1) clearly . theorem is proved. Xiechen Zhao sense of heart failure , Professor Wood , Professor Xue Weimin guidance and enthusiasm to help j 2 array Tsinghua : Huan P Pi ring 5 minutes